The Point-Slope Form Of The Equation Of The Line That Passes Through (20134, 20133) And (12, 1) Is Y 2013 1 = (X 2013 12). What Is The Standard Form O

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

 

Answer:

x - 4y = 8

Step-by-step explanation:

first, get the slope (m)

m = (1- -3 )/ (12 - -4) = 4 / 16 = 1/4

substitute to the point-slope form of the equation

y - 1 = m(x - 12)

y- 1 = (1/4) (x - 12)

multiply both sides with 4

4y - 4 = x -12

transform to standard form

x - 4y = 8