A 10-Lb Object Is Suspended By A String From An Overhead Support.?, A Horizontal Force Of 5.8 Pounds Is Applied On The Object. The Measure Of The Angl

A 10-lb object is suspended by a string from an overhead support.?

A horizontal force of 5.8 pounds is applied on the object. The measure of the angle which the string makes with the horizontal is???

Answer:

φ=60°

Step by step explanation:

Before the horizontal force F is applied:

The gravitational force keeps the string stretched. The string reacts to the gravitational force W by pulling the object upwards with the same amount of force : T=W

After the horizontal force is applied:

The string tilts to one side while the tension T of the string changes direction and finally stops moving when it reaches a static equilibrium with F.

This statement can be written in algebraic form:

Vertically:

F_{y}=0T_{y}-W=0 ⇔Tsin(φ) =mgC ⇔ T=mgC/sin(φ)

where C=1/32.17, for the imperial system of units to be coherent.

Horizontally:

F_{x}=0F-T_{x}=0 ⇔ F=Tcos(φ)

This is a system of equations, we will solve it by eliminating T.

Substitute T from the previous equation:

F=mgC cos(φ)/sin(φ) ⇔ sin(φ)/cos(φ)=mgC/F ⇔

tan(φ)=\frac{10 *32.17*\frac{1}{32.17} }{5.8} =\frac{10}{5.8} =1.72

⇔ φ≅60°

In the attached picture you can see the tension T being split into its components on the horizontal and the vertical axis.

Keywords: Force components, Static equilibrium, System of equations

Related Links:

brainly.ph/question/1392042

brainly.ph/question/1576716

brainly.ph/question/2069382


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